Как из c получить al4c3
Перейти к содержимому

Как из c получить al4c3

  • автор:

4 Al (s) + 3 C (s) → Al 4 C 3 (s)

Это окислительно-восстановительная (редокс) реакция:

3 C 0 + 12 e — → 3 C -IV (восстановле́ние)

4 Al 0 — 12 e — → 4 Al III (окисление)

C является окислителем, Al является восстановителем.

  • Al
    • Названия: Алюминийисточник: wikidata, дата обращения: 2019-09-07 , Порошок алюминияисточник: ICSC, дата обращения: 2019-09-04 , Alисточник: wikidata, дата обращения: 2019-09-07
    • Внешность (состояние): От серебристо-белого до серого цвета порошок источник: ICSC, дата обращения: 2019-09-04
  • C
    • Названия: Технический углеродисточник: wikidata, дата обращения: 2019-09-02 , Черный угольисточник: ICSC, дата обращения: 2019-09-04 , ТУисточник: wikidata, дата обращения: 2019-09-02 , Техуглеродисточник: wikidata, дата обращения: 2019-09-02
    • Внешность (состояние): Не имеющий запаха черный гранулированный или чрезвычайно мелкий порошок источник: ICSC, дата обращения: 2019-09-04
  • Al 4 C 3
    • Названия: Карбид алюминияисточник: wikipedia, дата обращения: 2019-09-28источник: wikidata, дата обращения: 2019-09-02 , Трикарбид тетраалюминияисточник: wikidata, дата обращения: 2019-09-02
    • Внешность (состояние): Светло жёлто-коричневые кристаллы без запаха источник: wikipedia, дата обращения: 2019-09-28

Al4C3 = Al + C — Balanced Chemical Equation

Thermodynamics of the reaction can be calculated using a lookup table.

Choose Compound States
Enthalpy Calculator

Is the Reaction Exothermic or Endothermic?
Al4C3 (s) 1 mol -207.27536 kJ/mol 207.27536 kJ
Al (s) 4 mol 0 kJ/mol 0 kJ
C (g) 3 mol 716.681544 kJ/mol 2150.044632 kJ
ΣΔH°f(reactants) -207.27536 kJ
ΣΔH°f(products) 2150.044632 kJ
ΔH°rxn 2357.319992 kJ

ΣΔH°f(products) > ΣΔH°f(reactants), so Al4C3 = Al + C is endothermic (absorbs heat).
Entropy Calculator

Is the Reaction Exoentropic or Endoentropic?

ΔS = Sproducts — Sreactants. If ΔS < 0, it is exoentropic. If ΔS >0, it is endoentropic.

Al4C3 (s) 1 mol 104.6 J/(mol K) -104.6 J/K
Al (s) 4 mol 28.32568 J/(mol K) 113.30272 J/K
C (g) 3 mol 157.9865848 J/(mol K) 473.9597544 J/K
ΣΔS°(reactants) 104.6 J/K
ΣΔS°(products) 587.2624744 J/K
ΔS°rxn 482.6624744 J/K

ΣΔS°(products) > ΣΔS°(reactants), so Al4C3 = Al + C is endoentropic (increase in entropy).
Gibbs Free Energy Calculator

Is the Reaction Exergonic or Endergonic?

ΔG = Gproducts — Greactants. If ΔG < 0, it is exergonic. If ΔG >0, it is endergonic.

Al4C3 (s) 1 mol -238.44616 kJ/mol 238.44616 kJ
Al (s) 4 mol 0 kJ/mol 0 kJ
C (g) 3 mol 671.289328 kJ/mol 2013.867984 kJ
ΣΔG°(reactants) -238.44616 kJ
ΣΔG°(products) 2013.867984 kJ
ΔG°rxn 2252.314144 kJ

ΣΔG°(products) > ΣΔG°(reactants), so Al4C3 = Al + C is endergonic (absorbs energy).

Reaction Expressions

Equilibrium Constant & Reaction Quotient
Kc or Q = ( [Al] 4 [C] 3 ) / ( [Al4C3] )

(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.)

Rate of Reaction
rate = -(Δ[Al4C3] / Δt) = 1/4 * (Δ[Al] / Δt) = 1/3 * (Δ[C] / Δt)
(assuming constant volume in a closed system and no accumulation of intermediates or side products)

  • Algebraic Method
  • Using Inspection

Balance Al4C3 = Al + C Using the Algebraic Method

To balance the equation Al4C3 = Al + C using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients. a Al4C3 = b Al + c C

Step 2: Create a System of Equations

Create an equation for each element (Al, C) where each term represents the number of atoms of the element in each reactant or product.

Al: 4a = 1b + 0c C: 3a = 0b + 1c 

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to solve for each variable.
Using Substitution or Elimination

  • 4a — 1b = 0
  • 3a — 1c = 0

Using Linear Systems / Algebra

Use your graphing calculator’s rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:

[ 4 -1 0 0] [ 3 0 -1 0]

The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients.

Simplify the result to get the lowest, whole integer values.

  • a = 1 (Al4C3)
  • b = 4 (Al)
  • c = 3 (C)

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced. Al4C3 = 4 Al + 3 C

Reactants Products
Al 4 4 ✔️
C 3 3 ✔️

Since there is an equal number of each element in the reactants and products of Al4C3 = 4Al + 3C, the equation is balanced.

Balance Al4C3 = Al + C Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in Al4C3 = Al + C must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.

Step 1: Count the number of each element on the left and right hand sides

Reactants (Left Hand Side) Products (Right Hand Side)
Reactants Products
Al4C3 Total Al C Total
Al 4 4 1 1
C 3 3 1 1

Step 2: Multiply coefficients for compounds to balance out each element

Al is not balanced. Add 3 molecules of Al to the product (right-hand) side to balance Aluminium:
Al4C3 = 4 Al + C

Reactants Products
Al 4 4 ✔️
C 3 1

C is not balanced. Add 2 molecules of C to the product (right-hand) side to balance Carbon:
Al4C3 = 4 Al + 3 C

Reactants Products
Al 4 4 ✔️
C 3 3 ✔️

Step 3: Verify that the equation is balanced

Since there are an equal number of atoms of each element on both sides, the equation is balanced.

Al4C3 = 4 Al + 3 C

Practice Balancing

Chemical Equation Balancer

Instructions

To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

  • Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
  • Ionic charges are not yet supported and will be ignored.
  • Replace immutable groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
  • Compound states [like (s) (aq) or (g)] are not required.
  • You can use parenthesis () or brackets [].

Examples

  • Aluminium Carbide = Aluminium + Carbon
  • Al + C + B2O3 = Al2O3 + B4C
  • Al + C + Cr2O3 = Cr3C2 + Al2O3
  • Al + C + H2O = Al(OH)3 + CH4
  • Al + C + O = Al2(CO3)3
  • Al + C + O = AlCO
  • Al + C + O2 = Al(CO3)3
  • Al + C + O2 = Al2(CO3)3
  • Al + C + O2 = AlCO3
  • H2O2 + KClO3 = KCl + O2 + H2O
  • CH2O + Br2 + H2O = CH2O2 + HBr
  • Na2SO3 + HI = INa + H2SO3
  • MgCo3 + HNo3 = Mg(No3)2 + H2Co3
  • Recently Balanced Equations

How to Balance Chemical Equations

Balance any equation or reaction using this chemical equation balancer! Find out what type of reaction occured.

Read our article on how to balance chemical equations or ask for help in our chat.

You can also ask for help or report an issue with the chemical equation balancer in our chat or forums.

Calculators

Equations & Reactions

  • Chemical Equation Balancer
  • Reaction Stoichiometry Calculator
  • Limiting Reagent Calculator
  • Ionic Equation Calculator
  • Redox Calculator

Al + C = Al4C3 — Balanced Chemical Equation

Thermodynamics of the reaction can be calculated using a lookup table.

Choose Compound States
Enthalpy Calculator

Is the Reaction Exothermic or Endothermic?
Al (s) 4 mol 0 kJ/mol -0 kJ
C (g) 3 mol 716.681544 kJ/mol -2150.044632 kJ
Al4C3 (s) 1 mol -207.27536 kJ/mol -207.27536 kJ
ΣΔH°f(reactants) 2150.044632 kJ
ΣΔH°f(products) -207.27536 kJ
ΔH°rxn -2357.319992 kJ

ΣΔH°f(reactants) > ΣΔH°f(products), so Al + C = Al4C3 is exothermic (releases heat).
Entropy Calculator

Is the Reaction Exoentropic or Endoentropic?

ΔS = Sproducts — Sreactants. If ΔS < 0, it is exoentropic. If ΔS >0, it is endoentropic.

Al (s) 4 mol 28.32568 J/(mol K) -113.30272 J/K
C (g) 3 mol 157.9865848 J/(mol K) -473.9597544 J/K
Al4C3 (s) 1 mol 104.6 J/(mol K) 104.6 J/K
ΣΔS°(reactants) 587.2624744 J/K
ΣΔS°(products) 104.6 J/K
ΔS°rxn -482.6624744 J/K

ΣΔS°(reactants) > ΣΔS°(products), so Al + C = Al4C3 is exoentropic (decrease in entropy).
Gibbs Free Energy Calculator

Is the Reaction Exergonic or Endergonic?

ΔG = Gproducts — Greactants. If ΔG < 0, it is exergonic. If ΔG >0, it is endergonic.

Al (s) 4 mol 0 kJ/mol -0 kJ
C (g) 3 mol 671.289328 kJ/mol -2013.867984 kJ
Al4C3 (s) 1 mol -238.44616 kJ/mol -238.44616 kJ
ΣΔG°(reactants) 2013.867984 kJ
ΣΔG°(products) -238.44616 kJ
ΔG°rxn -2252.314144 kJ

ΣΔG°(reactants) > ΣΔG°(products), so Al + C = Al4C3 is exergonic (releases energy).

Reaction Expressions

Equilibrium Constant & Reaction Quotient
Kc or Q = ( [Al4C3] ) / ( [Al] 4 [C] 3 )

(assuming all reactants and products are aqueous. substitutue 1 for any solids/liquids, and Psubstance for gases.)

Rate of Reaction
rate = -1/4 * (Δ[Al] / Δt) = -1/3 * (Δ[C] / Δt) = (Δ[Al4C3] / Δt)
(assuming constant volume in a closed system and no accumulation of intermediates or side products)

  • Algebraic Method
  • Using Inspection

Balance Al + C = Al4C3 Using the Algebraic Method

To balance the equation Al + C = Al4C3 using the algebraic method step-by-step, you must have experience solving systems of linear equations. The most common methods are substitution/elimination and linear algebra, but any similar method will work.

Step 1: Label Each Compound With a Variable

Label each compound (reactant or product) in the equation with a variable to represent the unknown coefficients. a Al + b C = c Al4C3

Step 2: Create a System of Equations

Create an equation for each element (Al, C) where each term represents the number of atoms of the element in each reactant or product.

Al: 1a + 0b = 4c C: 0a + 1b = 3c 

Step 3: Solve For All Variables

Use substitution, Gaussian elimination, or a calculator to solve for each variable.
Using Substitution or Elimination

  • 1a — 4c = 0
  • 1b — 3c = 0

Using Linear Systems / Algebra

Use your graphing calculator’s rref() function (or an online rref calculator) to convert the following matrix into reduced row-echelon-form:

[ 1 0 -4 0] [ 0 1 -3 0]

The resulting matrix can be used to determine the coefficients. In the case of a single solution, the last column of the matrix will contain the coefficients.

Simplify the result to get the lowest, whole integer values.

  • a = 4 (Al)
  • b = 3 (C)
  • c = 1 (Al4C3)

Step 4: Substitute Coefficients and Verify Result

Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced. 4 Al + 3 C = Al4C3

Reactants Products
Al 4 4 ✔️
C 3 3 ✔️

Since there is an equal number of each element in the reactants and products of 4Al + 3C = Al4C3, the equation is balanced.

Balance Al + C = Al4C3 Using Inspection

The law of conservation of mass states that matter cannot be created or destroyed, which means there must be the same number atoms at the end of a chemical reaction as at the beginning. To be balanced, every element in Al + C = Al4C3 must have the same number of atoms on each side of the equation. When using the inspection method (also known as the trial-and-error method), this principle is used to balance one element at a time until both sides are equal and the chemical equation is balanced.

Step 1: Count the number of each element on the left and right hand sides

Reactants (Left Hand Side) Products (Right Hand Side)
Reactants Products
Al C Total Al4C3 Total
Al 1 1 4 4
C 1 1 3 3

Step 2: Multiply coefficients for compounds to balance out each element

Al is not balanced. Add 3 molecules of Al to the reactant (left-hand) side to balance Aluminium:
4 Al + C = Al4C3

Reactants Products
Al 4 4 ✔️
C 1 3

C is not balanced. Add 2 molecules of C to the reactant (left-hand) side to balance Carbon:
4 Al + 3 C = Al4C3

Reactants Products
Al 4 4 ✔️
C 3 3 ✔️

Step 3: Verify that the equation is balanced

Since there are an equal number of atoms of each element on both sides, the equation is balanced.

4 Al + 3 C = Al4C3

Practice Balancing

Chemical Equation Balancer

Instructions

To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above.

  • Use uppercase for the first character in the element and lowercase for the second character. Examples: Fe, Au, Co, Br, C, O, N, F.
  • Ionic charges are not yet supported and will be ignored.
  • Replace immutable groups in compounds to avoid ambiguity. For example, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced, but XC2H5 + O2 = XOH + CO2 + H2O will.
  • Compound states [like (s) (aq) or (g)] are not required.
  • You can use parenthesis () or brackets [].

Examples

  • Aluminium + Carbon = Aluminium Carbide
  • Al + C + B2O3 = Al2O3 + B4C
  • Al + C + Cr2O3 = Cr3C2 + Al2O3
  • Al + C + H2O = Al(OH)3 + CH4
  • Al + C + O = Al2(CO3)3
  • Al + C + O = AlCO
  • Al + C + O2 = Al(CO3)3
  • Al + C + O2 = Al2(CO3)3
  • Al + C + O2 = AlCO3
  • MgCo3 + HNo3 = Mg(No3)2 + H2Co3
  • Cl + Na2SO3 + NaOH = Na2SO4 + NaCl + H2O
  • (NH4)2SO4 + Ag(NO3) = Ag2(SO4) + NH4(NO3)
  • Na2SO3 + HI = INa + H2SO3
  • Recently Balanced Equations

How to Balance Chemical Equations

Balance any equation or reaction using this chemical equation balancer! Find out what type of reaction occured.

Read our article on how to balance chemical equations or ask for help in our chat.

You can also ask for help or report an issue with the chemical equation balancer in our chat or forums.

Calculators

Equations & Reactions

  • Chemical Equation Balancer
  • Reaction Stoichiometry Calculator
  • Limiting Reagent Calculator
  • Ionic Equation Calculator
  • Redox Calculator

Калькулятор химических реакций

Для уравнивания химической реакции, введите уравнение реакции и нажмите кнопку Уравнять. Решенное уравнение появится сверху.

  • Используйте заглавные символы для начального знака элемента и строчные символы для второго знака. Примеры: Fe, Au, Co, Br, C, O, N, F.
  • Ионные заряды пока не поддерживаются и не будут приняты в расчет.
  • Переместите неизменные группы в соединениях, чтобы не допустить неопределенность. Например, C6H5C2H5 + O2 = C6H5OH + CO2 + H2O не уравняется, но XC2H5 + O2 = XOH + CO2 + H2O уравняется.
  • Промежуточные расстояния [такие, как (s) (aq) или (g)] не требуются.
  • Вы можете использовать круглые () и квадратные скобки [].

Примеры

  • Al4C3 + Ba(OH)2 + H2O = CH4 + Ba(Al(OH)4)2
  • Al4C3 + Ba(OH)2 + H2O = CH4 + Ba(AlO2)2
  • Al4C3 + Br2 = AlBr3 + C
  • Al4C3 + Br2 = AlBr3 + CBr4
  • Al4C3 + BrH = AlBr3 + CH4
  • Al4C3 + C = Al3C4
  • Al4C3 + C3 + H2O = Al(OH)3 + CH4
  • Al4C3 + CH3COOH + CO5 = (CH3COO)3Al + CH4
  • CH3CHClCH2Cl + NaOH = CH3CCH + NaCl + H2O
  • Fe3O4 + HF = FeF3 + FeF2 + H2O
  • CH2(OH)COOH + NaOH = CH2(ONa)COONa + H2O
  • Na2SO3 + HI = INa + H2SO3
  • Последние решенные уравнения

Как уравнять химическую реакцию

Прочитайте нашу статью на Как уравнивать уравнения либо попросите помощи в нашем чате.

Уравняйте любое химическое уравнение или реакцию с помощью этого калькулятора! Узнайте, какой тип реакции необходим.

Калькуляторы

Химическое уравнение

  • Программа решения химических уравнений
  • Калькулятор стехиометрических реакций
  • Калькулятор Лимитирующего реагента
  • Ionic Equation Calculator
  • окислительно-восстановительные реакции

химическое соединение

  • Калькулятор эмпирических формул
  • Калькулятор молярной массы
  • Калькулятор числа окисления

Добавить комментарий

Ваш адрес email не будет опубликован. Обязательные поля помечены *